根号b^2-1/4ac写成程序语句表达式是?

sqrt(b*b - 1/(4*a*c))

------------------
or

void main(void)
{
float a,b,c;
float x,y,z;

float precision = 0.000001;

printf(c\nPlease input the the value of a.\n");
scanf("%f", &a);
printf("\n");

printf("\nPlease input the the value of b.\n");
scanf("%f", &b);
printf("\n");

printf("\nPlease input the the value of c.\n");
scanf("%f", &c);
printf("\n");

x = b*b;
y = 4*a*c;

if( (y < precision) && (y > -precision ) )
{
printf("\n4ac is too closed to zero, can not get the result of b*b - 1/(4ac)\n");

return;
}

z = x - 1/y;
if( z < precision )
{
printf("\nb*b - 1/(4ac) is less than zero, can not get the result